To solve the problem of calculating the area of the figure composed of a rectangle and a semicircle, follow these steps:
Area of rectangle = length × width
[A_{\text{rectangle}} = 10 \times 6 = 60\ \text{cm}^2]
Area of semicircle = (\frac{1}{2} \pi r^2)
Using (\pi ≈ 3.14):
[A_{\text{semicircle}} = \frac{1}{2} \times 3.14 \times 3^2 = \frac{1}{2} \times 3.14 \times 9 = 14.13\ \text{cm}^2]
Add the areas of the rectangle and the semicircle:
[A{\text{total}} = A{\text{rectangle}} + A_{\text{semicircle}} = 60 + 14.13 = 74.13\ \text{cm}^2]
Answer: (\boxed{74.13}) square centimeters. (Or (\boxed{60 + \frac{9\pi}{2}}) if leaving in terms of π.)
For practical purposes, the numerical value is (\boxed{74.13}).
(\boxed{74.13})
(免責(zé)聲明:本文為本網(wǎng)站出于傳播商業(yè)信息之目的進(jìn)行轉(zhuǎn)載發(fā)布,不代表本網(wǎng)站的觀點(diǎn)及立場(chǎng)。本文所涉文、圖、音視頻等資料的一切權(quán)利和法律責(zé)任歸材料提供方所有和承擔(dān)。本網(wǎng)站對(duì)此資訊文字、圖片等所有信息的真實(shí)性不作任何保證或承諾,亦不構(gòu)成任何購買、投資等建議,據(jù)此操作者風(fēng)險(xiǎn)自擔(dān)。) 本文為轉(zhuǎn)載內(nèi)容,授權(quán)事宜請(qǐng)聯(lián)系原著作權(quán)人,如有侵權(quán),請(qǐng)聯(lián)系本網(wǎng)進(jìn)行刪除。