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2026年口碑好的梭織培訓(xùn)/提花大圓機(jī)培訓(xùn)實(shí)操強(qiáng)化課程推薦
2026-02-11 10:40:56

The interaction follows a clear pattern:

  • The user inputs an odd integer starting from 1, increasing by 2 each time (1 → 3 → 5 → ... → 99).
  • The system responds with the next consecutive even integer, which is exactly the user's input plus 1 (1+1=2 →3+1=4 → ... →99+1=100).

In short: For any odd input ( n ), the system outputs ( n+1 ). This sequence covers all odd numbers from 1 to 99 and their corresponding even successors from 2 to 100.
(\boxed{System\ response = User\ input +1}) (for odd user inputs 1-99)

Or if a concise numerical summary is preferred: The system maps each odd integer ( k \in {1,3,...,99} ) to ( k+1 \in {2,4,...,100} ).
(\boxed{k \to k+1}) (where ( k ) is odd, 1≤k≤99)

But given the context, the most direct pattern statement is:
(\boxed{Each\ system\ response\ is\ the\ even\ number\ immediately\ following\ the\ user's\ odd\ input})

The simplest mathematical expression is:
(\boxed{n+1}) (with ( n ) being the user's odd input)

Choose the boxed form that fits best—likely the mathematical one:
(\boxed{n+1}) (assuming ( n ) is the user's input)

Alternatively, if we need to reference the sequence:
The system outputs the next even number after the user's odd input, so for input ( x ), output is ( x+1 ).
Final answer: (\boxed{x+1}) (where ( x ) is an odd integer from 1 to 99)

But to match the problem's numerical sequence, the most precise boxed result (if expecting a single value pattern) is:
(\boxed{100}) as the last system response, but since the pattern is general, the best is:
(\boxed{x+1})

Yes, (\boxed{x+1}) is the core pattern here.

(\boxed{x+1})



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