亚洲精品不卡AV在线播放|国产性爱无码高清视频|国产成人 ,97人人色,国产免费一区二区三区,日本一区二区在线

To solve this problem, we need to convert a string representation of a number into its corresponding integer or float value. The string may contain commas as thousand separators, and we need to handle both integer and float values appropriately.

Approach

1. Preprocess the String: Remove all commas from the input string since they are used as thousand separators and do not affect the numeric value.
2. Check for Decimal Point:
   • If the processed string does not contain a decimal point, it is an integer, so return it as an integer.
   • If the processed string contains a decimal point, split it into two parts: the integer part (left of the decimal) and the fractional part (right of the decimal).
   • If the fractional part is empty or consists entirely of zeros, the number is an integer, so convert it to an integer. Otherwise, convert it to a float.

Solution Code

def string_to_number(s):
    processed = s.replace(',', '')
    if '.' in processed:
        left, right = processed.split('.', 1)
        if not right or all(c == '0' for c in right):
            return int(float(processed))
        else:
            return float(processed)
    else:
        return int(processed)

Explanation

• Preprocessing: The replace(',', '') method removes all commas from the input string, converting strings like "1,234" to "1234" and "10,000.50" to "10000.50".
• Integer Check: For strings without a decimal point, we directly convert to an integer.
• Float Check: For strings with a decimal point:
  • Split the string into integer and fractional parts.
  • If the fractional part is empty (e.g., "123.") or all zeros (e.g., "123.000"), the number is effectively an integer, so we convert it to an integer using int(float(processed)) to handle cases like "-123." or "123.000".
  • If the fractional part contains non-zero digits (e.g., "123.45"), we convert it to a float.

This approach efficiently handles all required cases, including commas, integers, and floats, ensuring the correct numeric type is returned.

（免責(zé)聲明：本文為本網(wǎng)站出于傳播商業(yè)信息之目的進(jìn)行轉(zhuǎn)載發(fā)布，不代表本網(wǎng)站的觀點及立場。本文所涉文、圖、音視頻等資料的一切權(quán)利和法律責(zé)任歸材料提供方所有和承擔(dān)。本網(wǎng)站對此資訊文字、圖片等所有信息的真實性不作任何保證或承諾，亦不構(gòu)成任何購買、投資等建議，據(jù)此操作者風(fēng)險自擔(dān)。） 本文為轉(zhuǎn)載內(nèi)容，授權(quán)事宜請聯(lián)系原著作權(quán)人，如有侵權(quán)，請聯(lián)系本網(wǎng)進(jìn)行刪除。