To address the common questions related to the sodium thiosulfate and sulfuric acid reaction experiment (where the cross disappears due to sulfur precipitate), here are the key explanations based on collision theory:
The reaction is:
$$\text{Na}_2\text{S}_2\text{O}_3 + \text{H}_2\text{SO}_4 \rightarrow \text{Na}_2\text{SO}_4 + \text{SO}_2 + \text{S↓} + \text{H}_2\text{O}$$
Insoluble sulfur ($\text{S↓}$) clouds the solution, obscuring a cross under the beaker. The time taken for the cross to disappear indicates reaction rate (shorter time = faster rate).
Increasing temperature:
Result: Faster reaction rate → sulfur forms quicker → cross disappears sooner.
Higher concentration of Na?S?O? or H?SO?:
Result: Faster reaction rate → sulfur precipitates faster → shorter time for cross to vanish.
The time taken depends on the reaction rate, which is governed by collision theory: more effective collisions (due to temp/concentration changes) lead to faster product formation (sulfur), thus reducing the time for the cross to disappear.
If your question was specific (e.g., about a particular factor), let me know and I can refine the answer further!
Example Answer for Temp Effect:
"Increasing temperature increases reactant particles' kinetic energy, causing more frequent and effective collisions. This speeds up the reaction, so the sulfur needed to block the cross forms faster, reducing time."
Example Answer for Concentration Effect:
"Higher Na?S?O? concentration means more particles per volume, increasing collision frequency. The reaction rate rises, so the cross disappears quicker."
These are standard explanations for this classic experiment (common in GCSE/IGCSE chemistry). Let me know if you need more details!
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