To solve this problem, we need to determine if the integer returned by the given function get_answer() is even. An even number is defined as any integer that is divisible by 2 with no remainder.
The approach to solve this problem involves two main steps:
get_answer() function to get the integer result.%), where num % 2 == 0 will be True if num is even, and False otherwise.def is_answer_even():
return get_answer() % 2 == 0
get_answer() is called directly to get the integer value we need to check.%), we compute the remainder when the result from get_answer() is divided by 2. If the remainder is 0, the number is even, so the expression get_answer() % 2 == 0 returns True. Otherwise, it returns False.This approach efficiently checks the evenness of the result with a single line of code, ensuring correctness for all integers (positive, negative, or zero). For example:
get_answer() returns 6, 6 % 2 ==0 → True.get_answer() returns -3, -3%2 ==1 → False.get_answer() returns 0, 0%2 ==0 → True (since zero is even).Answer:
The function is_answer_even() as written above is the correct solution.
(免責(zé)聲明:本文為本網(wǎng)站出于傳播商業(yè)信息之目的進(jìn)行轉(zhuǎn)載發(fā)布,不代表本網(wǎng)站的觀點(diǎn)及立場(chǎng)。本文所涉文、圖、音視頻等資料的一切權(quán)利和法律責(zé)任歸材料提供方所有和承擔(dān)。本網(wǎng)站對(duì)此資訊文字、圖片等所有信息的真實(shí)性不作任何保證或承諾,亦不構(gòu)成任何購買、投資等建議,據(jù)此操作者風(fēng)險(xiǎn)自擔(dān)。) 本文為轉(zhuǎn)載內(nèi)容,授權(quán)事宜請(qǐng)聯(lián)系原著作權(quán)人,如有侵權(quán),請(qǐng)聯(lián)系本網(wǎng)進(jìn)行刪除。