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To solve this problem, we need to identify all dates that correspond to the highest value in the given table. If multiple dates share the highest value, we return all such dates ordered chronologically.

Approach

The solution involves three key steps:

1. Find the Maximum Value: First, compute the highest value in the value column using the MAX() aggregate function.
2. Filter Dates: Select all dates where the value equals the computed maximum value.
3. Order Results: Sort the filtered dates in ascending order to ensure chronological order.

Solution Code

SELECT date 
FROM data 
WHERE value = (SELECT MAX(value) FROM data) 
ORDER BY date ASC;

Explanation

1. Subquery for Maximum Value: The subquery (SELECT MAX(value) FROM data) retrieves the highest value from the value column.
2. Filtering: The main query selects all rows from the table where the value matches the maximum value obtained from the subquery.
3. Ordering: The ORDER BY date ASC clause ensures the results are sorted in chronological order (since dates are stored in YYYY-MM-DD format, lexicographical order aligns with chronological order).

This approach efficiently narrows down the relevant dates and ensures the output is correctly ordered, making it both optimal and easy to understand. The solution handles ties (multiple dates with the same maximum value) correctly by returning all such dates.

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