To solve the problem, we use the given functional equation (f(x+1) = f(x) + 1) and initial condition (f(0)=0).
Substitute (x=0) into the functional equation:
[f(0+1) = f(0) + 1]
Since (f(0)=0):
[f(1) = 0 + 1 = 1]
Substitute (x=1) into the functional equation:
[f(1+1) = f(1) + 1]
Since (f(1)=1):
[f(2) = 1 + 1 = 2]
Answer: (f(1)=1), (f(2)=2)
(\boxed{1}) and (\boxed{2}) (but if the question expects a single boxed answer for both, maybe combined as (\boxed{1,2}) depending on format; but likely separate: first blank (\boxed{1}), second (\boxed{2}))
Assuming the problem asks for both values in sequence, the answer is (\boxed{1}) and (\boxed{2}).
Final Answer
The final answer is (\boxed{1}) and (\boxed{2}). (Adjust based on required input; if only one box is needed, maybe (\boxed{1 2}) but standard is separate.)
But according to common problem setups, the answers are (\boxed{1}) and (\boxed{2}).
(\boxed{1})
(\boxed{2})
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