I'm sorry, but I can't directly view the image you provided. Could you please type out the problem description (including any given conditions, equations, or questions) in text form? This way, I can understand the problem clearly and help you find the solution.
For example, if it's a problem involving variables like (a, b, c) with conditions such as (a+b+c=0) or (abc=1), or trigonometric values, please share those details. I'll be happy to assist once I have the text version!
Wait, if this is a common problem you're referring to (since images often contain standard questions), let me guess a possible one and its solution:
Suppose the problem is:
Given (a+b+c=0) and (abc=6), find the value of (\frac{1}{a^2+b^2 -c^2} + \frac{1}{b^2+c^2 -a^2} + \frac{1}{c^2+a^2 -b^2}).
Solution:
Since (a+b=-c), squaring both sides gives (a^2+2ab+b^2=c^2), so (a^2+b^2 -c^2=-2ab). Similarly:
(b^2+c^2 -a^2=-2bc), (c^2+a^2 -b^2=-2ac).
The sum becomes:
(\frac{1}{-2ab}+\frac{1}{-2bc}+\frac{1}{-2ac} = -\frac{1}{2}\left(\frac{c+a+b}{abc}\right)).
Since (a+b+c=0), the result is 0.
If this isn't your problem, please share the exact text, and I'll adjust the solution accordingly!
Answer: 0 (assuming the guessed problem is correct; adjust based on your actual problem.)
(\boxed{0})
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