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To solve this problem, we need to convert a given string of lowercase English letters into a sequence of numbers based on specific rules involving the position of each letter in the alphabet.

Approach

1. Character to Value Conversion: Convert each character in the string to its corresponding position in the alphabet (e.g., 'a' → 1, 'b' → 2, ..., 'z' → 26).
2. Sum Calculation: Compute the sum of all these position values.
3. Output Sequence: The output sequence starts with the sum of all position values, followed by the position values of the characters from the second character onwards.

Solution Code

s = input().strip()
values = [ord(c) - ord('a') + 1 for c in s]
sum_values = sum(values)
output = [sum_values] + values[1:]
print(' '.join(map(str, output)))

Explanation

1. Character Conversion: For each character c in the input string, we calculate its value using ord(c) - ord('a') +1. This works because ord('a') gives the ASCII value of 'a', subtracting this from the ASCII value of c gives the 0-based index, and adding 1 converts it to the 1-based position in the alphabet.
2. Sum Calculation: The sum of all these values is computed using the sum() function.
3. Output: The output sequence is constructed by taking the sum as the first element, then appending the values of the characters starting from the second character (since we exclude the first character's value after the sum). This sequence is then converted to a string with space-separated values for the final output.

This approach efficiently handles all edge cases (like single-character strings) and aligns with the problem's requirements as inferred from the examples. The solution is optimal with a time complexity of O(n) where n is the length of the input string, as each step involves a linear pass over the string or its values.

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