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It seems the image you provided cannot be viewed. Please type the content of the problem (in either Chinese or English), such as the integral to compute, the area to find, the derivative to calculate, etc. Once you provide the problem details, I will give you a detailed step-by-step solution.

Example of a Detailed Solution (for reference):

Suppose the problem is: Find the area enclosed by curves (y = x^2) and (y = 2x - x^2).

Step 1: Find intersection points of the curves

Set (x^2 = 2x - x^2):
[2x^2 - 2x = 0 \implies 2x(x-1) = 0 \implies x=0 \text{ or } x=1]

Step 2: Determine the upper and lower functions

For (0 < x < 1), take (x=0.5):

• (y = x^2 = 0.25)
• (y = 2x - x^2 = 1 - 0.25 = 0.75)
  Thus, (y = 2x - x^2) is the upper function, (y=x^2) is the lower function.

Step3: Compute the area integral

Area (A = \int{0}^{1} [\text{upper function} - \text{lower function}] dx):
[A = \int{0}^{1} (2x - x^2 - x^2) dx = \int_{0}^{1} (2x - 2x^2) dx]

Step4: Evaluate the integral

Antiderivative of (2x) is (x^2), antiderivative of (2x^2) is (\frac{2}{3}x^3):
[A = \left[ x^2 - \frac{2}{3}x^3 \right]_0^1 = (1 - \frac{2}{3}) - (0 -0) = \frac{1}{3}]

Answer: (\boxed{\frac{1}{3}})

Please share your specific problem, and I will help you solve it!

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