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To solve the problem of counting rectangles in a grid-like figure, we use the following key insight:

A rectangle is formed by selecting 2 distinct horizontal lines and 2 distinct vertical lines from the grid.

Formula:

If the figure consists of (M) rows of small squares and (N) columns of small squares:

• Number of horizontal lines = (M + 1) (since (M) rows of squares have (M+1) horizontal boundaries).
• Number of vertical lines = (N + 1) (similarly for columns).

The number of rectangles is:
[ \binom{M+1}{2} \times \binom{N+1}{2} ]
Where (\binom{k}{2} = \frac{k(k-1)}{2}) (choosing 2 lines from (k)).

Example Application:

Suppose your image shows a grid of 2 rows and 3 columns of small squares:

• Horizontal lines: (2+1=3), so (\binom{3}{2} = \frac{3×2}{2}=3).
• Vertical lines: (3+1=4), so (\binom{4}{2} = \frac{4×3}{2}=6).
• Total rectangles: (3×6=18).

Steps to get your answer:

1. Count the number of rows ((M)) and columns ((N)) of small squares in your image.
2. Apply the formula above using (M) and (N).

Let me know if you provide the grid dimensions, and I can compute the exact number!

(Assuming a common case, if the image was a 3x4 grid of squares, the answer would be (\binom{4}{2}×\binom{5}{2}=6×10=60).)

Final Answer (for a typical example): (\boxed{18}) (adjust based on your grid).

But if you need the exact value, please share the grid size from the image!

(\boxed{18}) (placeholder for a common case; replace with your calculation).

Wait, but since the image is missing, the best I can do is give the formula, but if I have to pick a common one, let's say the image was a 2x3 grid, so (\boxed{18}).

(\boxed{18})

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